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Abstract Senin, 29 Februari 2016
Mengenai Saya
Aping pong
puisi harapan bunda
Ikuti
Lihat profil lengkapku
Harapan Bunda Ku lukis indah sayap putri kecilku Kan terukir seribu cerita yang bahagia Tuk mampu terbang ke langit biru Temani malaikat yang tersipu malu
Arsip Blog
t 2016 (6) Maret (2)
Jemari telah menyapa Menari indah dan tertawa lepas Pesona ia bersimpul irama Di taman angkasa Sang Kuasa
t Februari (4) puisi harapan bunda 75 soal bahasa inggris Cerpen tata tertib
Wajah kecil yang sangat mungil Selalu ku manjakan dan ku timang Hanya sanggup terpukau Tanpa harus tinggal disana Inikah pintaku.... Ku sentuh itu dengan lembut Ku rangkai cita-citaku untuk anak ku
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75 soal matematika
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75 soal bahasa inggris 1. This text is for question 1. Eka : Are you free today ? Lidya : Yes, what’s up ? Eka : Would you like to come with me to see the “Peterpan” show to night ? Lidya : Thanks, I’d be delighted to. It’s my favourite band. What are the speakers going to do ? a. To stay at home. b. To see Peterpan show. c. To arrange their free time. d. To watch Peterpan at home. e. To come to their friend’s house. Answer : B 2. This text for question 2. Mira : Hi Dad. I will be late because the committee will hold a meet-ing after class. Fateher : It’s okay but you must go straight after the meeting. Mira : Don’t worry. Dad Mother : What did Mira say ? Father : She said that she would be late home today. What is the most possible place where Mira is talking to her father ? a. A hall b. Her home c. The office d. Her school e. A meeting room Answer : B This text for question 3 to 5. COMPANY ACCOUNTANT Expanding wholesaler of stationery and office equipment requires. With good salary and good working condition for good aplicant. Apply with curriculum vitae to Mrs. Barton. 3. In which section would you likely read the ad ? a. Company for sale b. Office equipment c. Job vacancy d. Entertainment Guide e. Stationery and office Answer C 4. What position is offered in the advertisement ? a. Salesman b. Wholesaler c. Accountant d. Office staff e. Director assistant Answer : B 5. Apply with curriculum vitae to Mrs. Barton. What information should the applicant include in it ? a. Experience in managing a company b. A statement of salary wanted c. A prove of knowing about stationery d. A statement of responsibility e. A statement of education and work experience Answer : E 6. “The goat did as he was asked ….” (p.3) What does the above sentence mean? a. The goat drunk enough and looked around b. The goat came down to the well and drank c. The goat called out loudly after the fox got out d. The goat waited someone who might help him e. The goat stood on his hind legs and put his forelegs against the side of the well Answer: E Text (For questions no 7 – 10 ) Forest are very important to keep the soil fertile and to prevent flood. The fallen leaves and decayed plants become humus which makes the soil rich and holds the rainwater. For many years, people have not been obeying the government’s regulations. They have been cutting down the trees carelessly. As a result, thousands of hectares of land have become worse and the rivers will be full of mud. In the wet season there will be erosion and floods which will destroy the farm lands and villages. 7. What is the main idea of paragraph 2? a. rivers are full b. land becomes infertile c. floods destroy villages d. erosions have caused floods e. deforestation has caused a lot of destruction Answer : C 8. The following statement are the advantages of forests mentioned in the text, EXCEPT …. a. they keep the soil fertile b. they prevent flood c. they produce humus d. they hold rainwater e. they produce fresh air Answer : E 9. Humus is made from …. a. fertile soil b. rown leaves c. the root of tree d. a kind of artificial fertilizer e. decayed plants and leaves Answer :E 10. The soil fertile and to prevent flood. The underlined word is synonymous to …. a. cause c. hinder b. move d. change e. produce Answer : C 11. It is stated that the university has goof relationship with.... a. Educational professionals b. Specialized technology c. Large universities d. Other campuses e. Industry Answer : E 12. “The University of Australia has an international educational reputation for....” The underline word means.... a. Knowledge b. Prestige c. Attitude d. Character e. Interest Answer : C Text 6. This text is for questions 13 to 16. (Soal Bahasa Inggris IPA dan Kunci Jawaban) The police thought that two burglars start the robbery at 151 Pattimura street on Sunday afternoon. The burglars broke into the students’ room while they are going to a football game. They never thought that while they were away, burglars would break into their boarding house. 13. What happened to the students’ room on Sunday afternoon ? a. The police broke it. b. The police ruined it c. Burglar broke into it. d. Two burglars broke it. e. The students started to ruin it. Answer : C 14. The burglars broke into the room when the students.... a. Were at a party b. Were taking a rest c. Were playing football d. Were at a football game e. Were watching football on TV Answer : C 15. “The burglars broke into the students room...” a. Broke forcefully b. Entered by force c. Put into pieces d. Easily entered e. Came into Answer : A 16. The students seem to think that .... a. They had locked theirs room b. Their boarding house was not safe c. Their boarding house was in safe area d. Thieves would easily break into their room e. There would be a robbery their boarding house Answer : C Text 7. This text is for questions 17 to 20. An elephant is the largest and strongest animals. It is a strange looking animal with its thick legs, huge sides and backs, large hanging ears, a small tall, little eyes, long white tusks and above all it has a long noise, the trunk. The trunk is the elephant’s peculiar feature, and it has various uses. The elephant draws up water by its trunk and can squirt it all over its body like a shower bath. It can also lift leaves and puts them into its mouth. In fact the trunk serves the elephant as a long am and hand. An elephant looks very clumsy and heavy and yet it can move very quickly. The elephant is a very intelligent animal. Its intelligence combined with its great strength makes it a very useful servant to man and it can be trained to serve in various ways such as carry heavy loads, hunt for tigers and even fight. (Soal dan Jawaban) 17. The third paragraph is mainly about the fact that.... a. Elephants are strong b. Elephants can lift logs c. Elephants are servants d. Elephant are very useful e. Elephant must be trained Answer : D 18. Which of the following is NOT part of the elephant describe in the first paragraph ? a. It looks strange b. It is heavy c. It is wild d. It has a trunk e. It has a small tail Answer : A 19. It is stated in the text that the elephant uses the trunk to do the following, EXCEPT.... a. To eat b. To push c. To drink d. To carry things e. To squirt water over the body. Answer : B 20. “The trunk is the elephant’s peculiar feature....(Paragraph2) The underline word close in meaning to .... a. Large b. Strange c. Tough d. Smooth e. King Answer : B 21. The melted butter is mixed together into …. a. the mixture of flour, egg and milk b. the mixture of milk and baking powder c. the mixture of egg and flour d. the mixture of baking powder, salt and egg e. the mixture of egg, flour and salt Answer : A Text (For questions no 22 – 23) Tom ! I am going to Anula supermarket to get some sugar. Would you like to turn the stove on when you are home? I have put some soup there. Just heat it for about 5 minutes and then take it out from stove before you have dinner 22. What is the message about ? a. Telling Tom to eat the soup b. Asking Tom to buy some sugar c. Asking Tom to go to supermarket d. Telling Tom to heat the soup e. Telling Tom to wait for about 5 minutes Answer : D 23. I’ve put the soup there. the word there refers to …. a. home b. kitchen c. the stove d. the supermarket e. Anula supermarket Answer : B Text (For questions no 24 – 26) Birds belong to a class of warm blooded vertebrate animals with feather covered bodies. Next to the animals, birds are the most important group of land-living vertebrates. All birds have feathers, although in some types, particularly those that cannot fly, the normal structure of the feathers may be much modified and be downy, woolly, or straw like. The forelimbs of birds are modified into wings. The bony part of the tail, except in the very earliest fossil birds is very short, and the visible tail is composed of feathers only. The teeth are absent except in some fossil forms. As in mammals the only other group of warm-blooded animal , the circulation is highly perfected so that there is no mixing of arterial and venous blood, but the arrangement of veins and arteries by which this is accomplished different in the two groups. Birds have keen hearing, although they have no external ears. The sense of sight also is very keen, but the sense of smell is weak or lacking, except few vultures and others birds. 24. The passage is about the …. of birds a. species b. definitions c. clarification d. classification e. characteristic Answer : E 25. From the text we can conclude that both birds and mammals have …. a. backbones b. keen sights c. keen hearing d. downy feathers e. weak sense of smell Answer : A 26. Which of the following is NOTpossessed by birds? a. Feathers b. Wings c. Teeth d. Tails e. Ears Answer : E Text (For questions no 27 – 28) - Soal Bahasa Inggris IPA dan Kunci Jawaban “Bisa Saja” is choosen as the first single of the album and theme song of BROWNIES, since the lyric reflects the story in the movie. Budjana of GIGI demonstrates his skills in playing acoustic guitar in “ Cinta Terakhir “. Three other brand new song “Dilema”, “Jangan Bilang Pacarku” and “ Semua Orang Berhak Mendapat Rasa Bahagia”, gives supporting nuances to the movie flow as GIGI composed them by imagining how the scenes would like look based on the screenplay. When Hanung Bramantyo, the director, and Dewa Budjana of GIGI chated, Budjana expressed his interest in making soundtrack album. Then, he recommended a few of GIGI songs, which the producer accepted because of the chemistry they created with the movie. Since GIGI can provide a variety of colors to add all kinds of musical nuances to enrich the movie, the producer deemed it unnecessary to find other musicians to complete OST of BROWNIES. Armand Maulana (vocalist), I Gede Dewa Budjana (guitarist), Thomas Ramdhan (Bass player) , and Gusti Erhandy (Drumstand-in player for Budhi haryono) put a lot of effort to this album. As a result, they’ve created perfect blend of movie and songs that makes BROWNIES tastier. It’s always fun to have a piece of Brownies in your mouth. But having it in your stereo set is more entertaining. No movie is perfect without musical score and OST of Brownies proved it excellent. 27. The passage is mainly about … a. the description how the album is accomplished through a series of steps b. an account of unusual or amusing incident retold by the album c. a review an of an original soundtrack of movie d. the process in making original soundtrack of movie e. an amusing story dealing with experience in different ways Answer : D 28. Which of the following statements is NOT TRUE according to the text? a. Budjana is the acoustic guitar player of GIGI b. “ Bisa Saja” is the theme song of BROWNIES c. Hanung Bramantyo is the director of GIGI band d. Armand Maulana is the vocalist of GIGI e. OST of BROWNIES is excellent Answer : C Text (For questions no 29 – 33) Is Smoking Good For Us? Before we smoke, it is better to look at the fact of smoking effects, not only for smokers but also for non smokers. About 50 thousands people die every year in Britain as the direct result of smoking. This is the seven times as many as deaths in road accidents. Nearly a quarter of smokers die because of diseases caused by smoking. Ninety percent of lung cancers are caused by smoking. If we smoke five cigarettes a day, we are six times more likely to die of lung cancer than a non- smoker. If we smoke twenty cigarettes a day, the risk is nineteen times greater. Ninety five percent of people who suffer from bronchitis are people who smoke. Smokers are two and half times more likely to die of heart disease than nonsmokers. Additionally, children of smokers are more likely to develop bronchitis and pneumonia. In one hour in a smoky room, a non-smoker breathes as much as substance causing cancer as if he had smoked fifteen cigarettes. Smoking is really good for tobacco companies because they do make much money from smoking habit. Smoking, however, is not good for everybody else. 29. What is the text about? a. A report of deaths caused by smoking b. The effects of smoking for people c. A calculation of how many cigarettes that may cause cancer d. Information of the effect of smoking to non smokers e. The result of smoking habit for tobacco companies Answer : C 30. Which one of the following statements is TRUE according to the text a. A supervisor was put in jail for two years. b. The supervisor gave many kinds of jobs to the maid. c. The maid has been working for him for two months. d. Winarti struck the supervisor with a remote control. e. The supervisor hit his maid’s head with the TV set’s remote control. Answer : E 31. “ ... he physically hurt the woman ...”(Paragraph 2) The underlined word is close in meaning to .... a. Cut b. Injured c. Offended d. Punished e. Damaged Answer : B 32. Why did Shafiq punch Winarti on her back? She was accused of .... a. Talking much time for herself b. Not working properly c. Working carelessly d. Daydreaming e. Being lazy Answer : D Text 11 This text is for questions 33 to 35. Singapore is a city state; it is a city but it is also a state. It is a republic. Along with Indonesia, Malaysia, Thailand, the Philippines and Brunei, it belongs to ASEAN, the Association of SouthEast Asian Nations. Like Indonesia, Singapore is a country of “Bhinneka Tunggal Ika.” Chinese, Malays, Indians and Eurasians make up its citizens. Other Asians, including Indonesians, Japanese, Philippines, Koreans, Thais and Arabs also live on that tiny island. Singapore is sometimes called “Instant Asia” because you can see varieties of customs, cultures, and foods of nearly all Asia in Singapore. 33. The text mainly talks about Singapore as .... a. A nation b. An island c. A republic d. A city state e. A member of ASEAN Answer : D 34. Singapore’s citizens consist of .... a. Brunei, Indians b. Chinese, Thais and Arab c. Chinese, Malays, Indians, and Eurasians d. Eurasians and Philippines e. Asians and Arabs Answer : C 35. “ .... Koreans, Tahis and Arabs live on that tiny island.” (Paragraph 2) The underlined word may be replaced by “ very .....” a. Cute b. Huge c. Small d. Broad e. Narrow Answer : C Text (For questions no 36 - 38) On Wednesday, my students and I went to Yogyakarta. We stayed at Dirgahayu hotel which is not far from Malioboro. On Thursday, we visited the temples in Prambanan. There are three big temples, the Brahmana, Syiwa and Wishnu Temples. They are really amazing. We visited only Brahmana and syiwa temples because Wisnu temple is being renovated On Friday morning, we went to Yogyakarta keraton. We spent two hours there. we were lucky because we led by a smart and friendly guide. Then we continued our journey to Borobodur. We arrived there at 4 pm. At 5 p.m we heard an announcement that Borobudur gate was closed. In the evening, we left for Jakarta by Wisata bus. 36. The text mainly discusses …. a. The writer’s trip to Yogyakarta b. The writer’s first visit to Prambanan c. The writer’s impression about the guide d. The writer’s experience at Yogyakarta keraton e. The writer’s impression about Borobudur Answer : D 37. Which temple is being renovated? a. Syiwa b. Wisnu c. Brahma d. Borobudur e. Syiwa and Wisnu Answer : B 38. Which of the following statement is TRUE? a. The writer and the students went to Yogyakarta for having a research b. The writer went to Borobudur first and then to keratin c. The writer was very disappointed with the guide d. Malioboro is very far from Dirgahayu Hotel e. The writer left for Jakarta on Friday Answer : E Text (For questions no 39 - 41) A fox fell into a well and couldn’t get out. By and by a thirsty goat comes along. Seeing the fox in the well, it asked if the water was good. “Good,” said the fox,” it’s the best water I’ve tasted in all my life. Come down and try it yourself”. The goat was thirsty so he got into the well. When he had drunk enough, he looked around but there was no way to get out. Then the fox said,” I have a good idea. You stand on your hind legs and put your forelegs against the side of the well. Then, I’ll climb on your back. From there, I’ll step on your horns and I can get out. And when I’m out. I’ll help you out of the well.” The goat did as he was asked and the fox got on his back and climbed out of the well. Then he coolly walked away. The goat called out loudly after him and reminded him of his promise to help him out. The fox merely turned to him and said,” If you only had thought carefully about getting out, you wouldn’t have jumped into the well “. The goat felt very sad. He called out loudly. An old man walking nearby heard him and put a plank into the well. The goat got out and thanked to the old man. 39. The text tells the story of …. a. A fox b. A goat c. A fox and a goat d. An old man and the fox e. The goat and an old man Answer : C 40. Paragraph two mainly tells …. a. How the fox helped the goat b. Why the fox got into the well c. How the fox got out of the well d. The fox’s idea to get out of the well e. How both the goat and the fox got out of the well Answer : D 41. …. transmitting texts and pictures …. The underlined word may be replaced by …. a. sending b. changing c. processing d. translating e. connecting Answer :C Text (For questions no 42 – 45) The Good Stepmother The old witch locked Hansel in a cage and set Gretel to clean the house. She planned to eat them both. Each night the children cried and begged the witch to let them go. Meanwhile, at home, their stepmother was beginning to wish she had never tried to get rid of the children. ”I must find them,” she said and set off into the forest. Many hours later, when her feet were tired from walking and her lips were dry from thirst, she came to the cottage belonging to the witch. The stepmother peeped through the window. Her heart cried out when she saw the two children. She picked up the broom leaning against the door and crept inside. The witch was putting some stew in the oven when the stepmother gave her an almighty push. The witch fell into the oven and the stepmother shut the door. “Children, I have come to save you,” she said, hugging them tightly. I have done a dreadful thing. I hope in time you will forgive me. Let me take you home and become a family again. They returned to their home and the stepmother became the best mother anyone could wish to have, and of course they lived happily ever after. 42. The story is about a stepmother who …. a. cried every night b. planned to eat her children c. begged a witch for money d. tried to run away from a witch e. Saved her children from a witch Answer : B 43. Which statement is TRUE about the stepmother? a. She was the witch’s friend. b. She loved her stepchildren. c. She hit the witch with a broom. d. She locked her children in a cage e. She visited the witch to see her children. Answer D 44. “The witch fell into the oven and the stepmother shut the door …. ” (p.4) The underlined word can be replaced by the word a. closed b. opened c. painted d. marked e. polished Answer : A 45. How did the witch die ? a. She was burnt in the oven b. She was trapped in a cage c. She was hit with a broom d. She was locked in her house e. She was pushed against the wall Answer : A Text (For questions no 46 – 48) Philipines : At least nine people were killed and dozens were injured when the Philipines security forces clashed with dozens of slum dwellers who resisted the tearing down of their homes in the northern province, a police commander said Tuesday. Raul Gonzales, the police chief in the northern Cordirella area, said that the soldiers and police officers traded gunfire with dozens of people who are illegally occupying the private land in Kalinga province. “our team was ambushed on their way to the community to be demolished,” said Gonzales. He added that the security only defended themselves after the residents dug foxholes and opened fire with automatic rifles. “nine people were killed and dozens were wounded, including 10 police officers during almost 10 hours of fighting. We even had to evacuate some of our officers who needed surgery to get the bullets from their bodies.”Reuters 46. What is the passage about? a. An illegal gunfire trade. b. A demolition of illegal slum dwellers. c. A fight between the police officers and the soldiers. d. A clash between the security forces and the slum dwellers. e. A clash between the police officers and the security officers Answer : A
47. The clash happened because …. a. illegal slum dwellers resisted the demolition of their home. b. the police officers and soldiers shot the dwellers. c. nine people were killed by the security forces. d. the police officers firing the dwellers. e. the people dwelled on private land. Answer :A 48. Raul Gonzales said that … a. ten police officers had to be evacuated. b. ten police officers were killed in the fighting. c. ten police officers were injured during the fighting d. some of the wounded people needed surgery. e. more than ten police officers were killed and injured an the fighting Answer : A Text (For questions no 49 – 50) The polar bear is a very big white bear. We call it the polar bear because it lives inside the Arctic Circle near the North Pole. There are no polar bears at the South Pole. The polar bears live at the North pole. There is only snow, ice, and water. There is not any land. These bears are three meters long, and weight 450 kilos. They can stand up on their back legs because they have very wide feed. They can use their front legs like arms. The Polar bears can swim very well. They can swim 120 kilometres out into the water. They catch fish and sea animals for food. They go into the sea when they are afraid. People like to kill the polar bears for their beautiful white coats. The governments of Canada, the united states and Russia say that no one can kill polar bears now. They do not want all of these beautiful animals to die. 49. What does the passage mainly discuss? a. The size of polar bears b. Where polar bears live c. The habitat of polar bears d. Why people hunt polar bears e. A brief description of polar bears. Answer : E 50. Which of the following statements is NOT TRUE about a polar bear? a. A polar bear weigh 450 kilos b. A polar bear is three meters lon c. A polar bear catches fish for food d. A polar bear goes into the sea when it is angry e. A polar bear can swim 120 km out into the water Answer : D 51. Dimas : Would you accompany me to the internet ? Bonar : … Dimas : Thanks. I really appreciate it. a. I’m disappointed b. I’m not so sure c. Sure d. Not at all e. I don’t know 52. Boni : How was your trip to Nias? Yudha : … with it. I want to go there again next year. a. I’m very pleased b. I’m really disappointed c. I’m very displeased d. I’m very unsatisfied e. I’m not happy 53. Endang : Hoe was your visit to the museum ? Ayu : It was closed when I got there … about it. Endang : I’m sorry to hear that a. I’m satisfied b. I’m happy c. I’m really content d. I’m Very disappointed e. I’m delighted 54. Arum : What do you think is the effective way to reduce global warming? Della : …… planting trees is one of the effective ways to reduce global warming. a. I don’t know b. How do you see c. I’m not sure d. In my opinion e. are you certain that 55. Aspani : ……. We help reduce global warming? Rini : I think we can help reduce global warming trough saving energy and recycling. a. What do b. Why should c. How can d. When can e. Where should 56. Aldo : … I would stay away from drugs Tius : Yes, I know. I’ll stay away from it a. I don’t want to say that b. I wouldn’t say c. If I were you d. I don’t think e. don’t think
57. Nanis : …. Get persuaded by drug peddlers Matias : OK. Don’t worry I won’t a. Make sure you b. Make sure you don’t c. I think you should d. be sure you e. you’d better 58. Elang : Look, the library is still open Endra : … I thought we can’t make it a. This is horrible b. I’m very unsatisfied c. Oh, this a bad d. Thank Goodness e. This is so disappointed 59. Agung : … Candra : I’m sorry. I didn’t mean to hit you a. Thank Goodness b. What a relief c. Whew! d. Terrific! e. Ouch! 60. Bella : What do you think of the book? Ajeng : … I really love it a. It’s terrific b. It’s disappointed c. It’s very unsatisfying d. it’s horrible e. it’s displeasing Read the text and the answer question below to 11 and 12 Dr. Scott The Chairman Of International Petroleum, Tbk. Jakarta & Mrs. Scott Simpson Cordially invite you to a Dinner Dance Party At their Residence in Kelapa Gading On Saturday, 3rd April at 9 p.m. 61 The party will start at ….. a. 6 p.m. b. 9 a.m. c. 7 p.m. d. 9 p.m. e. 10 a.m. 62. The purpose of the text is to …. a. describe a dinner dance party b. invite someone to a dinner dance party c. tell someone about s dinner dance party d. explain about a dinner dance party e. invite the chairman of international petroleum Read the text and the answer question below to 13 - 15 Attention, please! Due to some technical problems, the show will be delayed for about one hour. We apologize for the inconvenience. Thank You. 63. What is the announcement about? a. The delay of the show b. The inconvenience in the place c. The rule in the building d. The prohibition in the show e. The inconvenience 64. The following statements are TRUE according to the text, except ……. a. There are technical problems dealing with the show b. the show will be delayed for about two hours c. the committee of the show apologizes for the delay d. the announcement can be heard in a show e. the announcement can’t be heard 65. “………..the show will be delayed for…..” a. stopped b. started c. ended d. postponed e. don’t start Text 1 (for question number 66-73 Once there was a husband and his wife who had a baby. They had a dog named Bony. It was a very smart dog and faithful to them. The dog used to take care of the baby while were working in the rice field. One afternoon, while working in the field, they heard Bony barking. It was running toward them. It’s mouth smeared with blood. The husband shocked and thought that it had killed their baby. Suddenly he took his sickle and threw it to the dog. It hit the dog’s had and the dog head and the dog fell down and died. Hurriedly they got home and saw the baby sleeping. When the husband looked around in the baby’s room, he found a big snake lying on the floor. It was dead and blood spilled everywhere. It seemed the dog had killed the snake and the killed his faithful dog. 66. Who was Bony? Bonny was………. a. the husband’s name b. the wife’s name c. the bay’s name d. the dog’s name e. the snake’s name Answer: D 67. Why was the dog running toward the couple? a. because it afraid of snake b. because it was hurt c. because the dog wanted some foods. d. because the dog wanted to tell that something dangerous almost happened in their home. e. because a snake wanted to catch it. Answer: D 68. ……finally killed by the husband. a. the baby d. the dog b. the snake e. the couple c. the wife Answer: D 69. The snake was killed by………………… a. the dog d. the child b. the husband e. the baby c. the wife Answer: A 70. Was the baby hurt by the dog? a. yes, it is d. no was not b. yes, it was e. no, it doesn’t c. no, it did Answer: D
71. “Suddenly, he took his sickle …..”(paragraph 2, sentence 5). The word suddenly has the same meaning with the word……………… a. usually d. angrily b. quietly e. hungrily c. Quickly Answer: B 72. Why was the husband shocked? Because……………… a. He thought that the dog hurt killed his baby b. he was sick c. he saw a snake d. he saw a dog died e. his wife fell down Answer:A 73. A : “What kind of the narrative is it?” B : “It is……….” a. romance b. adventure c. science fiction d. mystery e. Folktale Answer:D 74. I …………..to the mall last week a. went d. goes b. go e. have gone c. Gone Answer:A 75. Lisa : Do you mind turning on the fan for me ? Mita : ………………….. a. no, thank you b. yes, I do c. l’d love to d. not at all e.yes, please Answer: D
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Cerpen tata tertib Kedisiplinan dan ketertiban di lingkungan sekolah memang sangatlah penting, karena hal ini sering kali terjadi pelanggaran kedisiplinan dan ketertiban yang dilakukan para siswa. Oleh sebab itu kedisiplinan dan ketertiban perlu kita atur dalam sebuah tatanan yang biasa kita sebut dengan tata tertib sekolah. Adapun dibuatnya tata tertib tersebut memiliki dua tujuan yaitu tujuan khusus dan juga tujuan umum. Secara khusus memiliki tujuan supaya kepala sekolah bisa menciptakan suasana yang kondusif bagi semua warga sekolah, supaya para guru bisa melaksanakan belajar mengajar dengan optimal dan supaya tercipta kerja sama di antara para orang tua dengan sekolah dalam mengemban tugas pendidikan. Sedangkan tujuan secara umumnya yaitu agar terlaksananya kurikulum secara baik serta bisa menunjang peningkatan mutu pendidikan di dalam sekolah. Untuk bisa menegakkan kedisiplinan di dalam lingkungan sekolah memang diperlukan tunjangan peraturan dengan ketentuan-ketentuan yang sifatnya mengikat setiap komponen baik itu guru, siswa maupun kepala sekolah guna mencapai tujuan yang sudah ditetapkan berupa tata tertib sekolah. Sementara untuk menegakkan tata tertib tersebut haruslah dimulai dari kelompok sekolah itu sendiri, dengan begitu maka sekolah bisa menjadi tempat dan sarana belajar dengan manajerial yang baik. Selain itu disiplin memang merupakan hal penting yang harus ditanamkan kepada anak didik kita di sekolah sedini mungkin, dengan tata tertib yang diterapkan setiap hari tersebut maka bisa membuat para siswa menjadi terbiasa untuk bersikap disiplin dan tertib. Kelas pun juga harus memiliki tata tertib sendiri yang harus dicontohkan dan dijelaskan kepada siswa agar dilaksanakan terus menerus. Beberapa taat tertib tersebut antara lain seperti : Masuk sekolah - Siswa diharuskan datang tepat waktu - Tas dan alat tulis ditaruh di laci meja, setelah itu keluar kelas - Bagi siswa yang mendapat giliran piket harus datang lebih awal - Bagi siswa yang tidak masuk harus membuat surat izin tertulis - Guru tidak boleh terlambat datang Di dalam kelas - Doa dipimpin ketua kelas -Memberikan salam pada guru - Guru melakukan absensi - Tidak boleh bercanda atau melakukan kegiatan lainnya ketika proses belajar - Siswa tidak boleh keluar kelas tanpa izin - Guru dilarang meninggalkan kelas saat pelajaran berlangsung Adapun beberapa manfaat yang bisa didapatkan dari adanya tata tertib sekolah, yaitu : Memberikan dukungan supaya terciptanya sikap ataupun perilaku yang tidak menyimpang Membantu para siswa untuk menyesuaikan diri dan memahami diri dengan tuntutan lingkungan Sebuah lingkungan sekolah yang tertib dapat memberikan gambaran lingkungan siswa yang gigih giat, penuh perhatian, serius dan kompetitif dalam pembelajarannya. Sehingga dengan adanya tata tertib sekolah tersebut diharapkan bisa memberikan andil besar terhadap lahirnya siswa yang berhasil serta berkepribadian yang unggul.
Diposting oleh Aping pong di 02.47
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75 soal matematika No. 1 a) Tentukan bayangan dari titik A (2, 3) oleh translasi T = (7, 8) b) Tentukan bayangan dari titik A (5, 10) oleh translasi c) Tentukan bayangan dari titik A (1, 2) oleh translasi T = (1, 2) dilanjutkan oleh translasi U = (3, 4) PembahasanBayangan dari titik A oleh suatu transformasi namakan A’ Dua model yang biasa dipakai sebagai berikut: Hasilnya akan sama saja, hanya sedikit beda cara penulisan, sehingga:a) Bayangan dari titik A (2, 3) oleh translasi T = (7, 8) b) Bayangan dari titik A (5, 10) oleh translasi
c) Bayangan dari titik A (1, 2) oleh translasi T = (1, 2) dilanjutkan oleh translasi U = (3, 4) Soal No. 2 Disediakan suatu persamaan garis lurusY = 3x + 5Tentukan persamaan garis lurus yang dihasilkan oleh translasi T = (2, 1) PembahasanAda beberapa cara diantaranya:Cara pertama: Posisi titik (x, y) oleh translasi T = (2, 1) adalah:x’ = x + 2 Õ x = x’ – 2 y’ = y + 1 Õ y = y’ – 1 Masukkan nilai x dan y yang baru ke persamaan asal y = 3x + 5(y’ – 1 ) = 3(x’ – 2) + 5 Tinggal selesaikan, ubah lambang y’ dan x’ ke y dan x lagi:y – 1 = 3x – 6 + 5y = 3x – 6 + 5 + 1 y = 3x Cara kedua:Ambil dua buah titik dari persamaan y = 3x + 5Misal: Titik A, untuk x = 0 Õ y = 5 dapat titik A (0, 5) Titik B, untuk Y = 0 Õ x = – 5 /3 dapat titik B (– 5/3 , 0)Translasikan Titik A dan B dengan T = (2,1)A’ (0 + 2, 5 +1) = A’ (2, 6)B’ (-5/3 + 2, 0 + 1) = A’ (1/3, 1)Buat persamaan garis yang melalui kedua titik itu: Cara ketigaDengan rumus yang sudah jadi atau rumus cepat: ax + by = c Translasi T (p, q) Hasil : ax + by = c + ap + bq Rumus ini untuk bentuk seperti soal di atas, jangan terapkan pada bentuk-bentuk yang lain, nanti salah.y = 3x + 5 atau3x − y = − 5 oleh T = (2,1)Hasil translasinya adalah:3x − y = − 5 + (3)(2) + (− 1)(1)3x − y = − 5 + 6 − 13x − y = 0atau y = 3xSoal No. 3Titik A memiliki koordinat (3, 5). Tentukan koordinat hasil pencerminan titik A:a) Terhadap garis x = 10b) Terhadap garis y = 8 PembahasanPencerminan sebuah titik terhadap garis x = h atau y = ka) Terhadap garis x = 10 x = h(a, b) ----------> (2h − a, b) x = h(3, 5) ----------> ( 2(10) − 3, 5) = (17, 5)b) Terhadap garis y = 8 y = k(a, b) ----------> (a, 2k − b) y = k(3, 5) ----------> ( 3, 2(8) − 5) = (3, 11)Soal No. 4Titik A memiliki koordinat (3, 5). Tentukan koordinat hasil pencerminan titik A:a) Terhadap garis y = xb) Terhadap garis y = − x Pembahasana) Terhadap garis y = x y = x(a, b) ----------> ( b, a) y = x(3, 5) ----------> (5, 3) b) Terhadap garis y = − x y = − x(a, b) ----------> ( − b, − a) y = − x(3, 5) ----------> (− 5, − 3) Soal No. 5Titik P (6√2, 10√2) diputar dengan arah berlawanan jarum jam sejauh 45° menghasilkan titik P'. Tentukan koordinat dari titik P'.PembahasanRotasi sebuah titik dengan sudut sebesar Sehingga: Catatan:sudut positif Õ berlawanan arah jarum jamsudut negatif Õ searah jarum jamSoal No. 6 Bayangan kurva y = x + 1 jika ditransformasikan oleh matriks kemudian dilanjutkan oleh pencerminan terhadap sumbu X adalah....A. x + y − 3 = 0B. x − y − 3 = 0C. x + y + 3 = 0D. 3x + y + 1 = 0E. x + 3y + 1 = 0(UN Matematika Tahun 2010 P04) Pembahasan Transformasi oleh matriks dilanjutkan pencerminan terhadap sumbu x dengan matriksnya Gabungan dua transformasi: Terlihat bahway' = − yy = − y'x' = x + 2yx' = x + 2(− y')x' = x − 2y'x = x' + 2y' Jadi:x = x' + 2y' y = − y'Masukkan ke persamaan awaly = x + 1(− y') = (x' + 2y' ) + 1x' + 3y' + 1 = 0 Sehingga bayangan kurva yang diminta adalah x + 3y + 1 = 0 Soal No. 7Koordinat bayangan titik P(6, 5) jika ditransformasikan oleh matriks dan dilanjutkan pencerminan terhadap sumbu X adalah....A. (−11, 6)B. (−6, 11)C. (−5, 11)D. (11, −5)E. (11, −6)PembahasanTitik A, dengan transformasi matriks akan menghasilkan titik A', yang koordinatnya: Dilanjutkan lagi dengan pencerminan terhadap sumbu X akan menghasilkan titik A'', dimana titik A'' koordinatnya akan menjadi (11, −6), beda tanda minus saja pada ordinat atau y nya. Bisa juga dengan mengalikan memakai matriks pencerminan terhadap sumbu X. Jadi A" koordinatnya adalah (11, −6) Soal No. 8Besar sudut antara vektor a = 2i − j + 3k dan b = i + 3j − 2k adalah....A. 1/8 B. 1/4 C. 1/3 D. 1/2 E. 2/3 (Soal Ebtanas 1988)PembahasanSudut antara dua buah vektor: Soal No. 9Ditentukan A(4 , 7 , 0) , B(6 , 10 , –6) dan C(1 , 9 , 0). AB dan AC wakil-wakil dari vektor u dan v. Besar sudut antara u dan v adalah....A. 0B. 1/4 C. 1/2 D. 3/4 E. (Soal Ebtanas 1989 - Vektor)PembahasanTentukan vektor u dan v terlebih dulu:u = AB = B − A = (6 , 10 , –6) − (4 , 7 , 0) = (2, 3, −6) Õ u = 2i + 3j − 6kv = AC = C − A = (1 , 9 , 0) − (4 , 7 , 0) = (− 3, 2, 0) Õ v = − 3i + 2j Sudut dengan nilai cosinus nol adalah 90° atau 1/2 Soal No. 10Diberikan tiga buah vektor masing-masing:a = 6p i + 2p j − 8 kb = −4 i + 8j + 10 kc = − 2 i + 3 j − 5 kJika vektor a tegak lurus b, maka vektor a − c adalah.....A. − 58 i − 20 j − 3kB. − 58 i − 23 j − 3kC. − 62 i − 17 j − 3kD. − 62 i − 20 j − 3kE. − 62 i − 23 j − 3k PembahasanTentukan nilai p terlebih dahulu, dua vektor yang tegak lurus maka perkalian titiknya sama dengan nol. a dan b tegak lurus maka berlaku: a ⋅ b = 0(6p i + 2p j − 8 k) ⋅ (−4 i + 8j + 10 k) = 0− 24p + 16p − 80 = 0− 8p = 80p = − 10Dengan demikian vektor a adalah a = 6p i + 2p j − 8 ka = 6(− 10) i + 2(− 10) j − 8 ka = −60 i − 20 j − 8 ka − c = ( −60 i − 20 j − 8 k) − (− 2 i + 3 j − 5 k) a − c = − 58 i − 23 j − 3k
Soal No. 11 Diberikan dua buah vektor masing-masing a = 9 dan b = 4. Nilai cosinus sudut antara kedua vektor adalah 1/3 . Tentukan: a) |a + b| b) |a – b| Pembahasan a) |a + b| Jumlah dua buah vektor
b) |a – b| Selisih dua buah vektor
Soal No. 12Dua buah matriks A dan B masing-masing berturut-turut sebagai berikut: Tentukan A − B PembahasanOperasi pengurangan matriks: Soal No. 13Dari dua buah matriks yang diberikan di bawah ini, Tentukan 2A + BPembahasanMengalikan matriks dengan sebuah bilangan kemudian dilanjutkan dengan penjumlahan: Soal No. 14Matriks P dan matriks Q sebagai berikut Tentukan matriks PQPembahasanPerkalian dua buah matriks Soal No. 15Tentukan nilai a + b + x + y dari matriks-matriks berikut ini Diketahui bahwa P = Q PembahasanKesamaan dua buah matriks, terlihat bahwa 3a = 9 Õ a = 32b = 10 Õ b = 52x = 12 Õ x = 6 y = 6 y = 2 Sehingga:a + b + x + y = 3 + 5 + 6 + 2 = 16Soal No. 16Tentukan determinan dari matriks A berikut ini PembahasanMenentukan determinan matriks ordo 2 x 2det A = |A| = ad − bc = (5)(2) − (1)(−3) = 10 + 3 = 13 Soal No. 17Diberikan sebuah matriks Tentukan invers dari matriks PPembahasanInvers matriks 2 x 2 Soal No. 18Tentukan tranpose dari matriks A berikut ini PembahasanTranspose sebuah matriks diperoleh dengan mengubah posisi baris menjadi kolom seperti contoh berikut: a + b + c + d = −5 − 3 + 6 + 5 = 3Soal No. 19Diketahui matriks Apabila B − A = Ct = transpos matriks C, maka nilai x .y =....A. 10B. 15C. 20D. 25E. 30 PembahasanTranspos C diperoleh dengan mengubah posisi baris ke kolom, B − A adalah pengurangan matriks B oleh A Akhirnya, dari kesamaan dua matriks:y − 4 = 1y = 5x + y − 2 = 7x + 5 − 2 = 7x + 3 = 7x = 4x . y = (4)(5) = 20Soal No. 20 Jika maka x + y =....A. − 15/4B. − 9/4C. 9/4D. 15/4E. 21/4PembahasanMasih tentang kesamaan dua buah matriks ditambah tentang materi bentuk pangkat, mulai dari persamaan yang lebih mudah dulu:3x − 2 = 73x = 7 + 23x = 9x = 34x + 2y = 822(x + 2y) = 2322x + 4y = 232x + 4y = 32(3) + 4y = 34y = 3 − 64y = − 3y = − 3/4Sehingga:x + y = 3 + (− 3/4) = 2 1/4 = 9/4 Soal No.21 Tentukan nilai x agar matrik merupakan sebuah matriks yang tidak memiliki invers!PembahasanMatriks yang tidak memiliki invers, disebut matrikssingular. Determinan dari matriks singular sama dengan nol.det P = ad − bc = 0(2)(x) − (3)(5) = 02x − 15 = 02x = 15x = 15/2Soal No. 22 Diketahui matriks , dan Jika A = B, maka a + b + c =.... A. − 7 B. − 5C. − 1D. 5E. 7PembahasanKesamaan dua matriks:4a = 12a = 3 3a = − 3b −3a = − 3b −3(3) = − 3b−9 = − 3bb = 33c = b3c = 3c = 1a + b + c = 3 + ( 3) + ( 1) = 7Soal No. 23 Diketahui matriks memenuhi AX = B, tentukan matriks XPembahasanJika AX = B, maka untuk mencari X adalah X = A−1 BCari invers matriks A terlebih dahulu, setelah ketemu kalikan dengan matriks B Soal No. 24Luas daerah parkir 1.760 m2. Luas rata-rata untuk mobil kecil 4 m2 dan mobil besar 20 m2. Daya tampung maksimum hanya 200 kendaraan. Biaya parkir mobil kecil Rp 1.000,00/jam dan mobil besar Rp 2.000,00/jam. Jika dalam satu jam terisi penuh dan tidak ada kendaraan pergi dan datang, maka hasil maksimum tempat parkir itu adalah.... A. Rp 176.000,00B. Rp 200.000,00C. Rp 260.000,00D. Rp 300.000,00E. Rp 340.000,00 PembahasanMembuat model matematika dari soal cerita di atasMisal:mobil kecil sebagai x, mobil besar sebagai y.Luas parkir 1760 m2:4x + 20 y ≤ 1760 disederhanakan menjadix + 5y ≤ 440.......(Garis I)Daya tampung lahan parkir 200 kendaraan:x + y ≤ 200 ..............(Garis II) Fungsi objektifnya adalah hasil parkiran:f(x, y) = 1000 x + 2000 y Membuat Sketsa Garis 1 dan garis 2Ubah tanda lebih besar atau lebih kecil menjadi tanda sama dengan terlebih dahulu,Garis 1x + 5y = 440Titik potong sumbu x, y = 0x + 5(0) = 440x = 440Dapat titik (440, 0)Titik potong sumbu y, x =00 + 5y = 440y = 440/5 = 88Dapat titik (0, 88)Garis 2x + y = 200Titik potong sumbu x, y = 0x + 0 = 200x = 200Dapat titik (200, 0)Titik potong sumbu y, x =00 + y = 200y = 200Dapat titik (0, 200)Menentukan titik potong garis 1 dan garis 2Untuk menentukan titik potong bisa dengan substitusi ataupun eliminasi.x + 5y = 440 x + y = 200 ____________ _4y = 240y = 60x + y =200x + 60 = 200x = 140Titik potong kedua garis aalah (140, 60)Berikut lukisan kedua garis dan titik potongnya, serta daerah yang diarsir adalah himpunan penyelesaian kedua pertidaksamaan di atas. Uji titik untuk mendapatkan fungsi obektif maksimum:Masukkan koordinat titik-titik uji / warna merah ke f(x, y) = 1000 x + 2000 yTitik (0,0) Õ f(x, y) = 1000 (0) + 200 (0) = 0Titik (200,0) Õ f(x, y) = 1000 (200) + 2000 (0) = 200 000Titik (0, 88) Õ f(x, y) = 1000 (0) + 2000 (88) = 176 000 Titik (140,60) Õ f(x, y) = 1000 (140) + 2000 (60) = 260 000 Dari uji titik terlihat hasil parkiran maksimum adalah Rp 260 000Soal No. 25Daerah yang diarsir pada gambar ialah himpunan penyelesaian suatu sistem pertidaksamaan linear. Nilai maksimum dari f (x, y) = 7x + 6y adalah....A . 88B. 94C. 102D. 106E. 196Pembahasan Cari persamaan kedua garis untuk dapat menentukan titik potongnya:Cara pertama dalam membuat persamaan garis y − y1 = m (x − x1)dengan m = Δy/ΔxPersamaan garis yang melalui titik (12, 0) dan (0, 20) adalah m = 20/−12 = − 5/3y − 20 = − 5/3 (x − 0)y − 20 = − 5/3 xy + 5/3 x = 203y + 5x = 60Persamaan garis yang melalui titik (18, 0) dan (0, 15) :m = 15/−18 = − 5/6y − 15 = − 5/6 (x − 0)y + 5/6 x = 156y + 5x = 90 Cara kedua dalam membuat persamaan garis bx + ay = ab Untuk garis yang memotong sumbu x di 12 dan y di 20 adalah: 20x + 12 y = 240 sederhanakan lagi 5x + 3y = 60 Untuk garis yang memotong sumbu x di 18 dan y di 15 adalah: 15x + 18y = 270 sederhanakan lagi 5x + 6y = 90 Titik potong kedua garis:6y + 5x = 903y + 5x = 60_________ -3y = 30y = 10 3(10) + 5x = 60 5x = 30x = 6Titik potong kedua garis adalah (6, 10)Uji titik: f (x, y) = 7x + 6yTitik (0, 0) Õ f (x, y) = 7(0) + 6(0) = 0Titik (12,0) Õ f (x, y) = 7(12) + 6(0) = 84Titik (0, 15) Õ f (x, y) = 7(0) + 6(15) = 90Titik (6, 10) Õ f (x, y) = 7(6) + 6(10) = 102Nilai maksimum tercapai saat x = 6 dan y = 10 yaitu 102Soal No. 26Suatu perusahaan meubel memerlukan 18 unsur A dan 24 unsur B per hari. Untuk membuat barang jenis I dibutuhkan 1 unsur A dan 2 unsur B, sedangkan untuk membuat barang jenis II dibutuhkan 3 unsur A dan 2 unsur B. Jika barang jenis I dijual seharga Rp 250.000,00 per unit dan barang jenis II dijual seharga Rp 400.000,00 per unit, maka agar penjualannya mencapai maksimum, berapa banyak masing-masing barang harus dibuat?A. 6 jenis IB. 12 jenis IIC. 6 jenis I dan 6 jenis IID. 3 jenis I dan 9 jenis IIE. 9 jenis I dan 3 jenis II PembahasanBarang I akan dibuat sebanyak x unitBarang II akan dibuat sebanyak y unitIlustrasi berikut untuk memudahkan pembuatan model matematikanya: x + 3y ≤ 182x + 2y ≤ 24Fungsi objektifnya:f(x, y) = 250000 x + 400000 yTitik potong x + 3y = 18 |x2| 2x + 2y = 24 |x 1| 2x + 6y = 362x + 2y = 24____________ _4y = 12y = 32x + 6(3) = 362x = 18x = 9Titik potong kedua garis (9, 3) Berikut grafik selengkapnya: Uji Titik ke f(x, y) = 250000 x + 400000 yTitik (0,0) f(x, y) = 250000 (0) + 400000 (0) = 0Titik (12, 0) f(x, y) = 250000 (12) + 400000 (0) = 3000 000Titik (9, 3) f(x, y) = 250000 (9) + 400000 (3) = 3450 000 Titik (0, 6) f(x, y) = 250000 (0) + 400000 (6) = 2400 000Dari uji titik terlihat hasil maksimum jika x = 9 dan y = 3 atau dibuat 9 barang jenis I dan 3 barang jenis II. Soal No. 27 Nilai minimum dari f(x,y) = 4x + 5y yang memenuhi pertidaksamaan 2x + y ≥ 7, x + y ≥ 5, x ≥ 0, dan y ≥ 0 adalah… A. 14 B. 20 C. 23 D. 25 E. 35 Pembahasan Langsung cari titik potongnya dulu: 2x + y = 7 x + y = 5 ------------ − x = 2 y = 3 Dapat titik A (2, 3) Berikut grafik selengkapnya:
Uji titik f(x, y) = 4x + 5y A(2, 3) = 4(2) + 5(3) = 23 B(5, 0) = 4(5) + 5(0) = 20 C(0, 7) = 4(0) + 5(7) = 35 Terlihat nilai minimumnya adalah 20.
Soal No.28Volume benda putar jika daerah yang dibatasi kurva y = − x2 + 4 dan y = − 2x + 4 diputar 360° mengelilingi sumbu Y adalah.....A. 8 satuan volumeB. 13/2 satuan volumeC. 4 satuan volumeD. 8/3 satuan volumeE. 5/4 satuan volume(Sumber Soal : UN Matematika SMA Tahun 2007) PembahasanLangkah pertama yang biasa ditempuh adalah membuat sketsa grafik kurva-kurva yang terlibat agar nampak batas-batas yang akan diambil, Kurva pertama bentuknya persamaan kuadrat,y = −x2 + 4Cari titik potong pada sumbu x, berarti y diberi harga nol, y = 0 y = −x2 + 40 = −x2 + 40 = 4 −x2 Faktorkan,0 = (x + 2)(x − 2)x = − 2 atau x = 2Titik-titik yang diperoleh dari langkah ini adalah (2, 0) dan titik (−2, 0)Titik potong pada sumbu y, berarti x diberi harga nol, x = 0y = −x2 + 4y = −02 + 4y = 4Titik yang diperoleh dari langkah ini adalah (0, 4) Kurva Kedua berbentuk persamaan liniery = − 2x + 4Titik potong sumbu x, berarti y = 0y = − 2x + 40 = − 2x + 42x = 4x = 4/2 = 2Diperoleh titik (2, 0)Titik potong sumbu y, berarti x = 0y = − 2x + 4y = − 2(0) + 4y = 4Diperoleh titik (0, 4)Grafik selengkapnya sebagai berikut Menentukan Batas-batasJika diputar pada sumbu x, terlihat dari gambar batas-batasnya adalah 0 dan 2Jika diputar pada sumbu y, terlihat batas-batasnya adalah 0 dan 4Kali ini akan dihitung untuk putar sumbu y, sehingga batas yang diambil 0 dan 4Dari rumus volume benda putar pada sumbu y untuk dua buah kurva:V = a òb ( [f1(y)]2 − [f2(y)]2 ) dyatauV = a òb ( [x1]2 − [x2]2 ) dy Õ Ubah bentuk "y =... " menjadi "x =..." atau "x2 =..." , y = −x2 + 4x2 = 4 − yy = − 2x + 4 2x = 4 − yx = 2 − 1/2 yx2 = 4 −2y + y2/4sehinggaV = a òb ( [x1]2 − [x2]2 ) dyV = 0 ò4 ( [4 − y] − [4 −2y + y2/4] ) dyV = 0 ò4 ( 4 − y − 4 + 2y − y2/4 ) dyV = 0 ò4 (y − y2/4 ) dyV = [ 1/2 y2 − y3/12]04V = (1/2 . 16 − 64/12) − (0) = 8/3 Soal No.29Perhatikan gambar diarsir di samping! Jika daerah yang diarsir diputar mengelilingi sumbu Y, maka volume benda putar yang terjadi adalah….A. 6 2/5 satuan volumeB. 8 satuan volumeC. 13 2/3 satuan volumeD. 15 1/3 satuan volumeE. 25 3/5 satuan volume Pembahasany = √xy2 = xy4 = x2x2 = y4 Dari rumus volume benda putar pada sumbu y untuk satu buah kurva:V = o ò2 x2 dyV = o ò2 y4 dyV = [ 1/5 y5 ]02 = 1/5 [ y5 ]02V = 1/5 [ (25) − (05) ] = 32/5 = 6 2/5 satuan volume Soal No.30Volume benda putar yang terbentuk dari daerah yang di kuadran I yang dibatasi oleh kurva x = 2√2 y2, sumbu Y, dan lingkaran x2 + y2 = 9, diputar mengelilingi sumbu Y adalah....A. 106/15 satuan volumeB. 124/15 satuan volumeC. 146/15 satuan volumeD. 164/15 satuan volumeE. 248/15 satuan volumePembahasanVolume benda putar pada sumbu Y. Kurva Ix = 2√2 y2x2 = 8y4Kurva IIx2 + y2 = 9x2 = 9 − y2Tentukan titik potongnya dulu8y4 = 9 − y28y4 + y2 − 9 = 0Faktorkan(8y2 + 9)(y2 - 1) = 0Ambil y2 - 1 = 0y2 = 1 Õ y = ± 1Sketsa kasar grafiknya sebagai berikut:
Soal No. 31Dua buah dadu dilempar undi sekali bersamaan. Peluang muncul jumlah mata dadu kurang dari 4 atau lebih dari 10 adalah....A. 1/12B. 1/9C. 1/6D. 1/3E. 5/12 PembahasanJumlah mata dadu kurang dari 4 Õ A = {(1, 1), (1, 2), (2, 1)} ada 3.Jumlah mata dadu lebih dari 10 Õ B = {(5, 6), (6, 5), (6, 6)} ada 3.P(A ÈB) = 3/36 + 3/36 = 6/36 = 1/6Soal No. 32Dua buah dadu dilempar undi bersama-sama sebanyak 144 kali. Frekuensi harapan munculnya mata dadu berjumlah 10 adalah....A. 12B. 20C. 24D. 36E. 40PembahasanJumlah mata dadu 10 Õ {(5, 5), (4, 6), (6, 4)} ada 3.Frekuensi harapan = 3/36 x 144 = 12Soal No. 33Pada bulan Januari, kelompok musik Melodi dan Gita Indah mengeluarkan CD baru mereka. Pada bulan Februari, kelompok musik Suara Merdu dan Pop Rock menyusul. Grafik berikut menggambarkan hasil penjualan CD dari bulan Januari sampai dengan bulan Juni. Manajer kelompok musik Gita Indah agak khawatir karena penjualan CD kelompok musiknya mengalami penurunan dari bulan Februari sampai dengan Juni. Berapa perkiraan penjualan CD kelompok musik ini pada bulan Juli, jika kecenderungan penurunan pada bulan-bulan sebelumnya terus berlanjut?A. 70 CD.B. 250 CD.C. 370 CD.D. 670 CD.E. 1.340 CD.Pembahasan Penurunan penjualan dari Gita indah sekitar 300 buah per bulan. Sehingga untuk bulan Juli perkiraannya adalah:650 - 300 = 350. Ambil yang paling dekat.Jawab: C. 370 CD.Soal No. 34 Median dari data pada histogram berikut adalah.... A. 10,5 tahunB. 11,5 tahunC. 12,5 tahunD. 13,5 tahunE. 14,5 tahunPembahasanJumlah frekuensi : 2 + 3 + 5 + 9 + 10 + 5 + 4 = 38Mediannya berada diantara nilai ke-19 dan nilai ke-20 Me = (12 + 15) /2 = 13,5 tahunSoal No. 35Diketahui data 3, 5, 6, 7, 5, 3, 6. Nilai simpangan baku data tersebut adalah....A. √2B. 2C. 2√2D. 4E. 6PembahasanRata-rata x- = (3 + 5 + 6 + 5 + 3 + 6) / 7 = 5S2 = [(3 -5)2 + (5-5)2 + (6-5)2 + (5-5)2 + (3-5)2 + (7-5)2 ] / 7S2 = 14/7 = 2Simpangan Baku SS = √2 Soal No. 36Suatu pabrik sandal memproduksi x pasang sandal setiap jam dengan biaya produksi (2x -60 + 600/x)ribu rupiah setiap pasang. Biaya produksi total minimum per jam adalah....A. Rp10.000,00B. Rp15.000,00C. Rp150.000,00D. Rp225.000,00E. Rp250.000,00 PembahasanPenggunaan turunan:Untuk memproduksi x pasang sandal diperlukan biaya dengan fungsinyaf(x) = (2x -60 + 600/x) x f(x) = (2x2 -60x + 600) ribuBiaya total minimum tercapai saat f ' (x) = 0 sehingga4x -60 = 0x = 15Jadi saat x = 15, biayanya adalah:f(x) = (2x2 -60x + 600) ribu= (2[15]2 -60[15] + 600) ribu = 150ribu rupiahJawab: C.Soal No. 37Hasil dari ò (4x3 + 3x2 -5)dx =....A. 12x2 + 6x + CB. 12x2 + 6x - 5 + CC. x4 + x3 + 5 + CD. x4 + x3 + CE. x4 + x3 -5x + CPembahasan ò (4x3 + 3x2 -5)dx= 4/4 x4 + 3/3 x3 -5x + C= x4 + x3 -5x + CJawab: E. Soal No. 38Luas daerah yang dibatasi oleh kurva y = -x2 + 4x + 5, sumbu X dan 1 ≤ x ≤ 4 adalah...A. 38 satuan luasB. 25 satuan luasC. 24 satuan luasD. 23 2/3 satuan luasE. 23 1/3 satuan luasPembahasan14 ò(-x2 + 4x + 5)dx= -1/3 x3 + 2x2 + 5x ]14= -1/3 (43 - 13) + 2(42 - 12 + 5(4 -1)= -21 + 30 + 15= 24 satuan luasSoal No. 39Pada suatu toko buah apel, jeruk, dan pepaya, Nina ingin membeli 9 buah pada toko tersebut. Jika Nina ingin membeli paling sedikit 2 buah untuk setiap jenis buah yang tersedia, maka komposisi banyak buah yang mungkin dapat dibeli adalah....A. 2B. 3C. 6D. 9E. 10PembahasanDalam setiap komposisi pembelian selalu terdapat 2 apel, 2 jeruk dan 2 pepaya (jumlahnya 6 buah), sehingga tinggal dicari komposisi dari 3 buah lainnya seperti berikut:003030300012021120102201210111Ada 10 kemungkinan yang bisa terjadi.Jawab: E.Soal No. 40Dari 6 orang pengurus karang taruna akan dibentuk panitia yang terdiri dari 1 orang ketua, 1 orang sekretaris, 1 orang bendahara dan 1 orang seksi acara. Banyak susunan panitia yang bisa dibentuk adalah....A. 720B. 360C. 120D. 30E. 6 PembahasanPermutasi 4 dari 6 orang yang ada:46P = 6! / (6-4)! = 6.5.4.3 = 360Jawab: B. Soal No. 41Suku pertama suatu barisan geometri sama dengan 4, sedangkan suku ke-3 sama dengan 144. Jika rasio barisan geometri tersebut positif, maka suku ke-5 sama dengan....A. 5.184B. 1.296C. 864D. 272E. 236 Pembahasanar2 = 144a = 44r2 = 144r2 = 36r = 6Suku ke-5= ar4= 4(6)4 = 5184Jawab: A Soal No. 42Jumlah tak hingga dari deret geometri 4 + 2 + 1 + 1/2 +.... adalah...A. 6B. 8C. 10 D. 12E. 13Pembahasana = 4r = 2/4 = 1/2Jumlah tak hingga S∞S∞ = a / (1 - r)= 4 / (1/2) = 8 Soal No. 43Suatu gedung pertunjukan mempunyai beberapa kursi. Setelah baris pertama, setiap baris mempunyai kursi 2 lebih banyak dari pada baris sebelumnya. Perbandingan banyak kursi pada baris ke-9 dan ke-6 adalah 4 : 3. Baris terakhir mempunyai 50 kursi. Banyak kursi yang dimiliki gedung tersebut adalah....A. 544 kursiB. 590 kursiC. 638 kursiD. 690 kursiE. 744 kursi PembahasanBarisan aritmetika:b = 24 : 3 = U9 : U6 4/3 = (a + 8b)/(a + 5b) 4/3 = (a + 16) / (a + 10) 4a + 40 = 3a + 48a = 8Baris terakhir mempunyai 50 kursi:a + (n - 1)b = 508 + (n - 1)2 = 50n - 1 = 21n = 22Banyak kursi:Sn = n/2 (a + Un)S22 = 22/2 (8 + 50) = 638 kursiJawab: C. Soal No. 44Nilai lim (x2 + 7x + 12) / (2x + 8) =....x Õ -4A. -1B. -1/2C. 7/8D. 3/2E. 7/2 Pembahasanlimit fungsi bentuk 0/0, dengan metode turunan:lim (2x + 7) / (2) = [2(-4) + 7 ] / 2 = -1/2x Õ -4Jawab: B. -1/2Soal No. 45Diketahui f(x) = 5x3 -3x2 -5x + 3 dan f ' (x) adalah turunan pertama dari f(x). Nilai f ' (2) =....A. 20B. 21C. 40D. 43E. 46PembahasanTurunan fungsi aljabar:f(x) = 5x3 -3x2 -5x + 3f ' (x) = 15x2 -6x -5f ' (2) = 15(2)2 -6(2) -5 f ' (2) = 60 - 12 - 5 = 43 Jawab: D. 43
Soal No. 46Diketahui matriks dan matriks Jika A + B = C, nilai (x + y)=....A. -1B. -4C. -5D. -6E. -8 PembahasanA + B = Cmaka4 + 2x = 22x = -2x = -14y + 5 = -114y = -16y = -4Jadi x + y = -1 + (-4) = -5Jawa: C. -5Soal No. 47Diketahui Determinan matriks (P + Q - 2R) adalah....A. -32B. -12C. 12D. 20E. 52PembahasanP + Q 2R Determinannya Jawab: B. -12Soal No. 48Diketahui matriks dan C = A - B. Invers matriks C adalah.... PembahasanMatriks C adalah Invers matriks C adalah Soal No. 49Jika matriks P adalah.... PembahasanPerkalian matriks, menentukan matriks P.P sama dengan invers matriks di depannya dikalikan matriks hasil perkalian Soal No. 50Pada suatu barisan aritmetika diketahui suku ke-8 adalah 31 dan suku ke14 adalah 55. Suku ke-22 dari barisan tersebut adalah....A. 83B. 84C. 86D. 87E. 91PembahasanSuku ke-8 adalah 31 dan suku ke14 adalah 55:U14 Õ a + 13b = 55U8 Õ a + 7b = 31-------------- -6b = 24b = 4Suku ke-22 adalah :U22 = U14 + 8b = 55 + 8(4) = 87Jawab: D. 87
Soal No.51Fungsi f(x) didefinisikan sebagai f(x) = x - 3 / 2x + 5, x ≠ -5/2 dan f-1(x) adalah invers dari fungsi f(x). Rumus f-1(x) adalah....A. 5x + 3 / 1 - 2x, x ≠ 1/2B. 5x - 3 / 1 - 2x, x ≠ 1/2C. 5x + 3 / 2x + 1, x ≠ -1/2D. 2x + 3 / 5x + 5, x ≠ -1E. 2x - 3 / 5x + 5, x ≠ -1 PembahasanFungsi invers dari bentuk f(x) = ax + b / cx + dadalah f-1(x) = -dx + b / cx - a sehingga:f-1(x) = -5x - 3 / 2x - 1 = 5x + 3 / 1 - 2xJawab: ASoal No. 52Akar-akar persamaan kuadrat 3x2 -5x -4 = 0 adalah x1 dan x2. Nilai dari 4/x12 + 4/x22adalah....A. 49/16B. 49/9C. 49/8D. 49/4E. 49/2PembahasanIngat perkalian dan jumlah akar-akar persamaan kuadrat:x1 + x2 = -b/a = 5/3x1 ⋅ x2 = c/a = -4/3dan x12 + x22 = (x1 + x2)2 -2x1x2Sehingga bentuk:4/x12 + 4/x22 = 4x22 + 4x12 / x12x22 = 4([x1 + x2]2 - 2x1x2) / (x1x2)2= 4([5/3]2 - 2(-4/3)) / (-4/3)2 = 49/4Soal No. 53Akar-akar persamaan kuadrat 2x2 +3x -5 = 0 adalah p dan q. Persamaan kuadrat baru yang akar-akarnya adalah 2p + 1, dan 2q + 1 adalah....A. x2 + x - 12 = 0B. x2 - x + 12 = 0C. x2 + x + 12 = 0D. -x2 + x - 12 = 0E. -x2 -x + 12 = 0Pembahasan2x2 +3x -5 = 0p + q = -b/a = -3/2p.q = c/a = -5/2Misalkan = 2p + 1 dan = 2q + 1, maka bentuk persamaan kuadrat yang baru adalah:x2 - ( + )x + ⋅ = 0x2 - (2p + 1 + 2q + 1)x + (2p + 1)(2q + 1) = 0x2 -2(p + q + 1)x + 4pq + 2(p + q) + 1 = 0x2 - 2(-3/2 + 1) + 4(-5/2) + 2(-3/2) + 1 = 0x2 + x - 12 = 0Soal No. 54Himpunan penyelesaian dari pertidaksamaan x2+ x - 12 < 0, untuk x Î R adalah.....A. {x | -3 < x < 4}B. {x | -4 < x < 3}C. {x | x < -4 atau x > 3}D. {x | x < -3 atau x > 4}E. {x | x < -2 atau x >6} Pembahasanx2 + x - 12 < 0 , pembuat nol adalah(x + 4)(x - 3) = 0x = -4 atau x = 3Dengan pengecekan garis bilangan diperoleh hasilnya adalah B. {x | -4 < x < 3}Soal No. 55Ditentukan x1 dan y1 memenuhi sistem persamaan linear 3x + 4y = 24 dan x + 2y = 10. Nilai dari 1/2 x1 + 2y1 =.....A. 4B. 6C. 7D. 8E. 14PembahasanMenentukan x, persamaan yang kedua dikalikan 23x + 4y = 24 2x + 4y = 20------------ - x = 4Menentukan y, persamaan kedua dikalikan 33x + 4y = 243x + 6y = 30---------- -2y = 6y = 3Jadi nilai 1/2 x1 + 2y1 = 1/2 (4) + 2(3) = 8 Soal No. 56Nilai dari 3log 81 + 2log 1/32 - 5log 5√5 =....A. 5/2B. 3/2C. 1/2D. - 3/2E. - 5/2 PembahasanBentuk logaritma:3log 81 + 2log 1/32 - 5log 5√5 = 3log 34 + 2log 2-5 - 5log 53/2= 4 - 5 - 3/2= - 1 - 3/2 = - 5/2 (E)Soal No. 57Koordinat titik potong grafik fungsi kuadrat f(x) = 2x2 2x - 12 dengan sumbu X dan sumbu Y berturut-turut adalah....A. (-3, 0), (2, 0), dan (0, -12)B. (-2, 0), (3, 0), dan (0, -12)C. (-2, 0), (3, 0), dan (0, 6)D. (-2, 0), (3, 0), dan (0, 12)E. (3, 0), (2, 0), dan (0, -12)PembahasanTitik potong grafik fungsi kuadrat:Sumbu X, saat nilai Y = 02x2 - 2x - 12 = 0x2 - x - 6 = 0(x - 3)(x + 2) = 0x = 3 Ú x = - 2 Diperoleh titik potong: (3, 0) dan (-2, 0)Titik potong sumbu Y, saat x = 0y = 2(0)2 - 2(0) - 12 = -12Diperoleh titik (0, -12)Jawab: B. (-2, 0), (3, 0), dan (0, -12)Soal No. 58Koordinat titik balik grafik fungsi kuadrat y = x2- 4x - 5 adalah....A. (-9, 2)B. (-2, -9)C. (-2, 9)D. (2, 9)E. (2, -9)PembahasanTitik balik saat:x = -b/2a = -(-4)/2(1) = 2Saat nilai x = 2, nilai y adalah:y = (2)2 - 4(2) - 5 = -9Diperoleh titik baliknya (2, -9)Jawab: E Soal No. 59Persamaan grafik fungsi pada gambar adalah.... A. y = x2 - 2x + 5B. y = x2 + 2x + 5C. y = x2 + 4x + 5D. y = x2 - 4x + 5E. y = x2 - 6x + 5 PembahasanCek titik baliknya dulu, dari gambar nilai -b/2a harus sama dengan 2:A. y = x2 - 2x + 5 Õ -b/2a = -(-2)/2(1) = 1B. y = x2 + 2x + 5 Õ -b/2a = -(2)/2(1) = -1C. y = x2 + 4x + 5 Õ -b/2a = -4/2(1) = -2D. y = x2 - 4x + 5 Õ -b/2a = -(-4)/2(1) = 2E. y = x2 - 6x + 5 Õ -b/2a = -(6)/2(1) = -3 Yang cocok adalah pilihan D.Jika lebih dari satu jawaban yang cocok baru cek titik lainnya.Soal No. 60Diketahui fungsi f : R Õ R dan g : R Õ yang didefinisikan f(x) = x - 5 dan g(x) = x2 - 3x - 4, komposisi fungsi (g o f)(x) =....A. x2 - 3x - 9B. x2 - 3x - 36C. x2 - 13x -14D. x2 - 13x + 6E. x2 13x + 36Pembahasan(g o f)(x) = (x - 5)2 - 3(x - 5) - 4 = x2 -10x + 25 -3x + 15 - 4= x2 -13x +36 Jawaban yang cocok adalah E. Soal No.61Himpunan penyelesaian persamaan cos 2x° + 7 sin x° − 4 = 0 , 0 ≤ x ≤ 360 adalah....A. {240, 300} B. {210, 330} C. {120, 240} D. {60, 120} E. {30, 150} Soal No.62Himpunan penyelesaian pesamaan sin2 2x − 2 sinx cosx − 2 = 0 , untuk 0° ≤ x ≤ 360° adalah....A. {45° , 135°} B. {135°, 180°} C. {45° , 225°} D. {135° , 225°} E. {135°, 315°} Soal No.63Himpunan penyelesaian persamaan sin 2x + 2 cos x = 0, untuk 0≤ x < 2 adalah....A. {0, }B. {/2, }C. {3/2, }D. {/2, 3/2}E. {0, 3/2} Soal No.64Himpunan penyelesaian persamaan cos 2x + cos x = 0, 0° ≤ x ≤ 180° adalah...A. {45°, 120°}B. {45°, 135°}C. {60°, 135°}D. {60°, 120°}E. {60°, 180°}Soal No.65Himpunan penyelesaian dari persamaan cos 4x + 3sin 2x = −1 untuk 0° ≤ x ≤ 180° adalah…A. {120°,150°}B. {150°,165°}C. {30°,150°}D. {30°,165°}E. {15°,105°}Soal No.66Himpunan penyelesaian persamaan cos 2x − 2 sin x = 1; 0 ≤ x < 2 adalah...A. {0, , 3/2, 2}B. {0, , 4/3, 2}C. {0, 2/3; , 2}D. {0, , 2}E. {0, , 3/2}Soal No.67Himpunan penyelesaian persamaan cos 2x + 5 sin x + 2 = 0 untuk 0 ≤ x ≤ 2 adalah…A. {2/3,4/3}B. {4/3, 5/3}C. {5/6, 7/6}D. {5/6, 11/6}E. {7/6, 11/6} Soal No.68Himpunan penyelesaian dari 2 sin2 x − 3 sin x + 1 = 0 dengan 0° ≤ x ≤360° adalah....A. {30°, 90°, 150° } B. {30°, 120°, 240°}OC. {30°, 120°, 300°}D. {30°, 150°, 270°} E. {60°, 120°, 270°}
Soal No.69 Diketahui sebuah kubus ABCD . EFGH. Besar sudut yang dibentuk oleh garis BG dengan BDHF adalah.... A. 90° B. 60° C. 45° D. 30° E. 15° Soal No.70 Perhatikan gambar kubus ABCD . EFGH ! Jarak bidang ACH dan EGB adalah .... A. 4 √3 cm B. 2 √3 cm C. 4 cm D. 6 cm E. 12 cm Soal No.71Diketahui kubus ABCD.EFGH dengan panjang rusuk 8 cm. Jarak titik H dan garis AC adalah..... A. 8 √3 cm B. 8 √2 cm C. 4 √6 cm D. 4 √3 cm E. 4 √2 cm Soal No.72Diketahui kubus ABCD.EFGH dengan panjang rusuk 6 cm. Jika sudut antara diagonal AG dengan bidang alas ABCD adalah , maka sin adalah ... A. 1/2 √3B. 1/2 √2C. 1/3 √3D. 1/2E. 1/3 √2Soal No.73Diketahui kubus ABCD.EFGH, panjang rusuk kubus 12 cm. Titik P terletak pada perpanjangan rusuk DC sehingga CP : DP = 1 : 3. Jarak titik P dengan bidang BDHF adalah ... A. 6 √2 cm B. 9 √2 cm C. 12√2 cm D. 16 √2 cm E. 18 √2 cm Soal No.74Balok ABCD.EFGH dengan panjang AB = BC = 3 cm dan AE = 5 cm. P terletak pada AD sehingga AP : PD = 1 : 2 dan Q pada FG sehingga FQ : QG = 2 : 1. Jika adalah sudut antara PQ dengan ABCD, maka tan =... A. 1/2 √5B. 1/10 √10C. 1/2 √10D. 1/7 √14E. 1/7 √35Soal No.75Diketahui kubus ABCD.EFGH dengan panjang rusuk 4 cm. Titik P adalah titik potong AH dan ED dan titik Q adalah titik potong FH dan EG. Jarak titik B dengan garis PG adalah....A. √22 cmB. √21 cmC. 2√5 cmD. √19 cm E. 3√2 cm
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