Jul 30, 2015 - Viva Questions 1. What is a weak acid? Weak acid is a weak electrolyte, which ionises incompletely in aqueous solution. 2. What is PKa of a weak acid? PKa is a modern method of expressing the strength of weak of acids. It is mathematic
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Science & Mathematics Chemistry
Determination of the dissociation constant of a weak acid, Ka? Pippete 25 mL of 0.1 M CH3 COOH into each of the two conical flasks, X and Y. NaOH is titrated with X. When endpoint is reached, volume of 0.2 M NaOH is recorded..The solution is then mixed with Y. The pH of this mixture is
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determined using the pH meter and Ka is calculated. It is said that Ka equals the... show more Follow
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Answers Best Answer: 0.1M HC2H3O2 x 0.025L = 0.0025moles HAc
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this requires 0.0025moles NaOH for neutralization which would be: 0.2M = 0.0025moles / ?L = 0.0125L NaOH
Which acid dissociation constant (Ka) indicates the weakest acid?
total volume of 1st flask = 0.0375L
Acid dissociation constant, ka for acetic acid?
moles C2H3O2- = 0.0025moles
Which acid dissociation constant represents the weakest acid?
0.0375L of 1st flask is added to 0.025L of 0.1MHAc 0.025L x 0.1M HAc = 0.0025moles HAc
Calculate acid dissociation constant Ka. known pH and concentration of C6H5COOH?
C2H3O2- from first flask = 0.0025moles = moles HAc in the second flask there are = number of moles present of both species in the same volume, therefore [C2H3O2-] = [HAc] in the second
Determining the Acid Dissociation Constant of a Weak Acid?
flask so, in the second flask, we have 0.04M C2H3O2-, 0.04M HAc. the HAc will dissociate to H+ and C2H3O2- but not completely.
Which sample of gold contains particles having the highest average kinetic energy?
when we set up the Ka equation, we see the following: Ka = [H+][C2H3O2-] / [HAc].....because [C2H3O2-] = [HAc], these cancel out, leaving
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Ka = [H+] Caroline Miller · 7 years ago 0
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What volume of 0.250 M Na3PO4 is required to precipitate all the lead(II) ions from 190.0 mL of 0.300 M Pb(NO3)2? Calculate X.?
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C6H5COOH + H2O H3O+ + C6H5COO- Ka = [H3O+][C6H5COO-]/C6H5COOH] because of the fact the a
Would this alien be theoretically possible? 6 answers
million mole acid promises a million mole each of H3O+ and C6H5COO- then neglecting water autoprotolysis [H3O+] = [CH3COO-] and so Ka = [H3O+]^2/[CH3COOH] provided the acid is vulnerable sufficient the concentration of undissociated acid can be taken as its analytical concentration (ie 0.02M). This sufficient if the [H3O+] is <
Is the following statement true or false? 5 answers
approximately 10% of the analytical interest. in this occasion [H+] = 10^-2.ninety six = a million.096 x 10^-3M. So Ka
How to make MSDS?
= (a million.096x10^-3)^2/0.02 = 6 x 10^-5 mol dm-3 The equilibrium concentrations are [H3O+] = [CH3COO-] = a
6 answers
million.096 x 10^-3, [CH3COOH] = (0.02 - a million.096x10^-3), [OH-] = 10^-14/a million.096x10^-3 if youin case you cant make the belief above concerning [CH3COOH] then you definitely have have been given to apply [CH3COOH] = (0.02-[H3O+]) in the expression for Ka, giving Ka = 6.35 x 10^-5
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