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block is released from rest after the spring is stretched a distance A = 0.13 m to the right. At that instant, find the

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Your Name: ___________________________ FINAL EXAM Print clearly. There are 25 equally-weighted questions on this test. There is only one correct answer per question. Clearly circle your answer. The second to last page is blank for extra space if needed. The formulas are on the last two pages so you can separate it for easy access. The key will be posted online after all make-up tests are completed. ************************************************************************* 1. A girl throws a ball up in the air and then catches it when it comes back down. At the ball’s highest point, what is true about the ball’s velocity and acceleration? Take up to be the positive direction. a) v < 0 and a < 0

b) v = 0 and a < 0

d) v = 0 and a > 0

e) v = 0 and a = 0

c) v > 0 and a > 0

2. A ball rolls horizontally off of a desk at a speed of 4.0 m/s. If the ball lands 2.0 m away from the base of the desk, how tall is the desk? a) 0.78 m

b) 1.2 m

c) 5.0 m

d) 1.0 m

e) 1.4 m

3. An object is on a frictionless inclined plane. The plane is inclined at an angle of 35º with the horizontal. What is the magnitude of the acceleration of the object? a) 1.3 m/s2

b) 5.6 m/s2

c) 8.0 m/s2

d) 4.9 m/s2

4. An athlete swings a 5.50-kg ball horizontally on the end of a rope. The ball moves in a circle of radius 0.750 m at an angular speed of 4.82 rad/s. What is the ball’s centripetal acceleration? a) 3.15 m/s2

b) 17.4 m/s2

c) 9.71 m/s2

d) 31.0 m/s2

e) 15.2 m/s2

5. The pressure at the bottom of a glass filled with ethyl alcohol (ρ = 806 kg/m3) is P. The ethyl alcohol is poured out and the glass is filled with water (ρ = 1000 kg/m3). The pressure at the bottom of the glass is now a) b) c) d)

smaller than P. equal to P. larger than P. unable to determine.

6. A wrench is fitted to a stuck bolt and makes an angle of 30⁰ with respect to the horizontal. The wrench is 0.45 m long and a force of 115 N is applied vertically downward at the end of the wrench farthest from the bolt. How much torque is applied to the bolt by this force. a) 25.9 N m

b) 44.8 N m

c) 51.8 N m

d) 59.6 N m

7. A wooden block is pulled 12 m across a frictionless surface using a rope. The tension in the rope is 30 N; and the net work done on the block is 291 J. What angle does the rope make with the horizontal? a) b) c) d) e)

72° 54° 36° 27° 15°

8. A 0.16 kg hockey puck is initially at rest on the ice. When the puck is struck by a hockey stick, the average force exerted on the puck is 250 N. If the puck’s speed after being struck is 12 m/s, how long was the stick in contact with the puck? a) 0.0006 s b) 0.008 s c) 0.05 s d) 0.1 s e) 1 s

9. How much energy is required to change a 30-g ice cube from ice at −25°C to steam at 130°C? Use the following table of values as needed. Freezing/melting point of water

0°C

a) 22,600 J

Boiling point of water

100°C

b) 46,300 J

Specific heat of ice

2,090 J/(kg · °C)

c) 53,800 J

Specific heat of water

4,186 J/(kg · °C)

d) 79,400 J

Specific heat of steam

2,010 J/(kg · °C)

e) 93,700 J

Latent heat of fusion for water

3.33 ✕ 105 J/kg

Latent heat of vaporization for water

2.26 ✕ 106 J/kg

10. It takes 1.67 x 106 J to melt a cup of ice cubes at 0 °C completely to water at 0 °C. What is the mass of the water? (Use the table from number 9.) a) b) c) d) e)

0.739 kg 799 kg 5.02 kg 399 kg 7.99 kg

11. Suppose you have 1 kg each of iron, ice, and water. Rank the amount of energy required to heat each sample by 20°C, from least energy to greatest energy. The specific heat of iron is 448 J/(kg · °C) and other values are in the table from number 9. a) iron, ice, water b) iron is the least, ice and water would require equal amounts of energy c) ice and water would require equal amounts of energy, iron is the greatest d) water, ice, iron e) ice, water, iron

12. A block of mass m = 0.63 kg is attached to a spring with force constant 150 N/m is free to move on a frictionless, horizontal surface as in the figure below. The block is released from rest after the spring is stretched a distance A = 0.13 m to the right. At that instant, find the force on the block. (Indicate the direction with the sign of your answer. Assume that the positive direction is to the right.) a) 0.082 N

b) -0.082 N

c) -19.5 N

d) 19.5 N

e) 94.5 N

13. A block of mass m = 0.63 kg is attached to a spring with force constant 150 N/m is free to move on a frictionless, horizontal surface as in the figure above (see number 12). The block is released from rest after the spring is stretched a distance A = 0.13 m to the right. At that instant, find the potential energy. a) 0.78 J

b) 9.8 J

c) 1.3 J

d) 5.7 J

e) 30 J

14. The sinusoidal wave shown in the figure below is traveling in the positive x-direction and has a frequency of 13.7 Hz. What is the wavelength? a) 5.20 cm b) 10.4 cm c) 8.26 cm d) 4.13 cm e) 13.7 cm

15. The sinusoidal wave shown in the figure below is traveling in the positive x-direction and has a frequency of 13.7 Hz. What is the speed of the wave? a) 142 m/s b) 71.2 m/s c) 113 m/s d) 1.42 m/s e) 0.71 m/s

16. When an object moving in simple harmonic motion is at its maximum displacement from equilibrium, which of the following is at its maximum? a) velocity

b) potential energy

c) kinetic energy

d) torque

17. There are two wave pulses on a string travelling towards each other as shown.

When the two pulses overlap, what will the string look like?

(a)

(b)

18. A pendulum has a mass of 0.75 kg and a length of 2.0 m. What is the period of oscillation of this pendulum? a) 10 s

b) 7.7 s

c) 2.8 s

d) 1.3 s

e) 14 s

19. What is the speed of sound in air at 30 °C? a) 110 m/s

b) 331 m/s

c) 343 m/s

d) 349 m/s

e) 352 m/s

20. A block of mass m = 0.75 kg is attached to a spring with force constant 239 N/m is free to move on a frictionless, horizontal surface. The block is released from rest after the spring is stretched a distance A = 0.20 m to the right. What is the maximum speed that the block moves with as it undergoes simple harmonic motion? a) 12.7 m/s

b) 9.52 m/s

c) 7.98 m/s

d) 5.27 m/s

e) 3.57 m/s

21. A pedestrian hears a car horn sound from a car 5 𝑚 away with an intensity 𝐼. What is the intensity of the car horn to a second pedestrian who is 15 𝑚 away from the same car? a) 9𝐼

b) 3𝐼

c) 𝐼

1

d) 𝐼 3

1

e) 𝐼 9

22. A sound wave takes 0.01 seconds to travel 50 m along a bar of metal. If the metal has a density of 8050 a) b) c) d) e)

𝑘𝑔 𝑚3

what is the young’s modulus of the metal?

4.03 × 107 𝑃𝑎 2.01 × 1011 𝑃𝑎 9.83 × 1010 𝑃𝑎 3.44 × 109 𝑃𝑎 7.80 × 1012 𝑃𝑎

23. A block with a mass of 15 kg is attached to the end of a horizontal spring and set into simple harmonic motion along a frictionless surface. What is the spring constant of the spring if the block moves with a frequency of 0.2 Hz? a) 23.7 N/m

b) 51.9 N/m

c) 18.8 N/m

d) 9.34 N/m

e) 12.9 N/m

24. The speed of a wave along a taught string is 175 m/s. If the string is under a tension of 65 N what is the mass per unit length of the string? a) 74.3 𝑔⁄𝑚 b) 16.8 𝑔⁄𝑚 c) 2.12 𝑔⁄𝑚 d) 371 𝑔⁄𝑚

e) 8.55 𝑔⁄𝑚

25. A block of mass M is attached to a horizontal spring set into simple harmonic motion along a frictionless table on earth and the period of oscillation is measured to be 𝑇𝐸 . If this system were moved to the moon which has an acceleration due to gravity that is much lower than that on earth how would the period change? a) b) c) d)

The period of oscillation on the moon would be greater than 𝑇𝐸 The period of oscillation on the moon would be equal to 𝑇𝐸 The period of oscillation on the moon would be less than 𝑇𝐸 More information is needed to answer.

Possibly Useful Information (bold indicates a vector) v = vo + a t

x = vot + ½ a t2

v2 = vo2 + 2 a x

1 in = 2.54 cm

W=mg

g = 9.8 m/s2

fk = k n

fs  s n

sin θ = opposite/hyp

cos θ = adjacent/hyp

tan θ = opposite/adj

a 2 + b2 = c 2

1 kg = 2.2 pounds

1 m = 3.28 ft quadratic: ax2+bx+c=0

Newton’s 1st Law: Newton’s 2nd Law:

x=(-b(b2-4ac)^½)/2a

Every object continues in its state of rest, or of constant speed in a straight line, until a nonzero net force acts on it. net F = m a

Newton’s 3rd Law:

When one object exerts a force on a second object, the second object exerts an equal and opposite force on the first object. ************************************************************************* Work = 𝐹|| ∆𝑥 = (component of force in the direction of displacement) (displacement) Kinetic Energy:

KE = ½ m v2

Work-Energy Theorem

Power = Work/time

𝑊𝑛𝑒𝑡 = 𝑊𝑛𝑐 + 𝑊𝑐 = ∆𝐾𝐸

Gravitational Potential Energy: Work done by gravity:

GPE = mgy where y is vertical position 𝑊𝑔 = −∆𝐺𝑃𝐸

Wnc + KEi + PEi = KEf + PEf

where Wnc is work done by frictional forces

KEi + PEi = KEf + PEf

if there is no friction

Momentum: p = m v

I (impulse) = change in momentum = F Δt

Conservation of momentum: m1v1i + m2v2i = m1v1f + m2v2f Elastic collision: v1i-v2i = -(v1f-v2f) Perfectly inelastic collision: m1v1i + m2v2i = (m1+ m2)vf

************************************************************************* θ=s/r ω = ∆θ/∆t α = ∆ω/∆t v=rω aT = r α aC = v2/r = r ω2 θ = ωot + ½ α t2

ω = ωo + α t

ω 2 = ω o2 + 2 α  θ

1 revolution = 2π rad

G = 6.673x10-11 N m2/kg2 F = G m1m2/r2

PEEarth = -G ME m/r KErot = ½ I ω 2

L=Iω

τ = r F⏊

τnet = I α = ∆L/∆t

I = Σmr2

KERi + KETi +PEi = KERf + KETf + PEf

Conservation of angular momentum: Li = Lf ρ = M/V

P = F/A

stress=elastic modulus x strain

F/A = S∆x/h (shear modulus)

F/A = Y ∆L/L0 (Young’s modulus)

∆P = -B ∆V/V (bulk modulus)

density of fresh water = 1.00 x 103 kg/m3

Area of a circle = πr2

P = P0 + ρgh B = ρVg

P1 + ½ ρv12 + ρgy1 = P2 + ½ ρv22 + ρgy2

A1v1 = A2v2

TC = T – 273.15

TF = 9/5 TC + 32

∆L = α L0 ∆T

∆A = γ A0 ∆T

∆V = β V0 ∆T

************************************************************************* Q = mc∆T Q = ± mL Fs = -kx

𝑚

𝑇 = 2π√ 𝑘 = 1/f

E = ½ kA2 = ½ mv2 + ½ kx2 x = A cos(2πft) = A cos(ω t)

v = -A ω sin(2πft) = -A ω sin(ω t)

a = -A ω2 cos(2πft) = -A ω2 cos(ω t) 𝐿

𝑇 = 2π√𝑔 𝐵

𝑣 = √ρ

amax = A ω2 𝐹

𝑣 = √𝜇

v = λf 𝑌

𝑣 = √ρ

I = P/A = P/(4πr2)

𝑘

𝑣 = √𝑚 (𝐴2 − 𝑥 2 )

PEs = ½ kx2

a = - (k/m) x

𝑇

𝑣 = 331 𝑚/𝑠√273K β = 10 log (I/I0)

I0 = 1.0 x 10-12 W/m2

𝑘

𝜔 = 2πf = √𝑚 vmax = A ω

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