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Need help with a probability problem blondii
#1
Oct 13, 2011
Hi All, I need a quick help with this problem i have been working with. I know the answer (from book). My question is how do I reach that answer. Now im not an expert in probability but I tried every way i can think of but to no avail. The Answer in the Book: 0.0960 Question: In a certain region of the country it is known from past experience that the probability of selecting an adult over 40 years of age with cancer is 0.05. If the probability of a doctor correctly diagnosing a person with cancer as having the disease is 0.78 and the probability of incorrectly diagnosing a person without cancer as having the disease is 0.06, what is the probability that an adult over 40 years of age is diagnosed as having cancer? Please if you can solve this problem with the answer above can you please kindly post your working out as well. Any help will be much appreciated. Phys.org - latest science and technology news stories on Phys.org • In Antarctic dry valleys, early signs of climate change-induced shifts in soil • Study on super-silenced DNA hints at new ways to reprogram cells • Team publishes research on unusual gene evolution in bacteria
SneakyPete
#2
Oct 13, 2011
Hi, blondii. I'll start with a disclaimer stating that I know next to nothing about probability mathematics, and very little about mathematics in general, but here's the solution that makes sense to me: In this area, it is assumed that 5% of people have cancer and 95% do not. Of the 5% who do, a doctor will make a correct diagnosis 78% of the time. .78 * .05 = .039 So there is a 3.9% chance that a person will a) have cancer, and b) receive an accurate diagnosis. Of the remaining 95%, 6% of them will receive a false positive diagnosis. .95 * .06 = .057 The combined probabilities of the two groups is 9.6%. Hope that helps, Pete
blondii
#3
Oct 13, 2011
Hi SneakyPete, thanks for your solution. Seems to make sense. Much appreciated.
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