Root Locus • Root Locus: a method of presenting graphical [PDF]

Disadvantage: More complicated. • Advantage: Faster ... Frequency Response. • Leads to 2 plots. • MG vs. ω ⇨ 20

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Root Locus

Transient Response Design via Gain Adjustment

• Root Locus: a method of presenting graphical information about a system’s behavior when the controller is working

• Design Procedure for Higher Order Systems 1. 2. 3. 4.

Sketch the RL Assume 2nd order system w/ no zeros Find K to meet transient response specs Verify positions of higher order poles to make sure assumptions are valid 5. If assumptions do not hold, simulate system numerically

• Common tool for design of closed loop systems • Allows us to sketch out system behavior for a range of K

• Rules (negative feedback systems): • Number of branches = close loop poles • Root Locus is symmetric about the real axis • The root locus segments lie on the real axis to the left of an odd number of open loop poles and zeros

• The root locus begins (0 gain) at the poles and ends (∞ gain) at the zeros (finite and infinite) of G(s)H(s)

• Asymptotes

• Break-out & Break-in Points 1

2

Compensator Configurations

PID Controller Design

• Cascade

1. 2. 3. 4. 5. 6. 7. 8.

• Feedback

3

Evaluate uncomp sys to get determine desired transient Design PD controller Simulate to check Redesign if necessary Design PI controller to yield desired steady-state error Determine K_1, K_2, and K_3 Simulate to check Redesign if necessary 4

1

PID Controller Design

1. 2. 3. 4. 5. 6. 7. 8.

Feedback Compensation

Evaluate uncomp sys to get determine desired transient Design PD controller Simulate to check Redesign if necessary Design PI controller to yield desired steady-state error Determine K_1, K_2, and K_3 Simulate to check Redesign if necessary

• Disadvantage: More complicated • Advantage: Faster response • Sometimes physical system characteristics does not allow us to use cascade compensators

• Often does not require additional amplification • Two Approaches 5

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Approach 1

Approach 2 • Design a minor loop’s transient response separately from the closed-loop system response. • Example 3: • ζ = 0.8 for minor • ζ = 0.6 for closed-loop

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2

Frequency Response

From Last Time

Definition:

• Frequency Response

• The frequency response of a linear system is the relationship between the gain and the phase of a sinusoidal input and the corresponding sinusoidal output.

• Leads to 2 plots

Note: • • • •

• MG vs. ω  20log10 (MG) vs. log10 (ω) • φG vs. ω  20log10 (MG) vs. log10 (ω)

Frequency response gives steady state response Complements analysis from root locus Often used to back out system parameters Not so good for transient analysis

}

Bode Plots

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Nyquist Criterion

Using Nyquist Criterion to Find K

Instead of F(s) = 1 + G(s)H(s), let F(s) = G(s)H(s)

Given

F(s)-plane

s-plane p0 x F(s)

z0

Step 1: Set K = 1, sketch poles & zeros in s-plane, sketch Nyquist diagram

x p1 C

-1 Γ

z1

Step 2: Find G(jω)H(jω)

p2 x

Step 3: Find point where Nyquist intersects negative real axis

Then, N = P – Z is the number of counterclockwise encirclements of -1

Step 4: Determine N for stability and then K 11

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3

Gain and Phase Margins

Frequency Response of the Lead Compensator

Gain Margin: change in open-loop gain (dB) at 180± to make closedloop system unstable

Determine Mc(ω)—φc(ω), given

Phase Margin: change in open-loop phase shift at unity gain to make closed-loop system unstable

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Design Procedure for Lead Compensation

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Design Procedure for Lag Compensator

1. Find closed-loop bandwidth requirement to meet Ts, Tp or Tr 2. Set K s.t. uncompensated system satisfies steady-state error specs 3. Plot Bode plots for set K and determine uncompensated system’s phase margin 4. Find phase margin to meet ζ or %OS, find phase contribution from Gc 5. Determine β 6. Determine |Gc(jω)| @ peak of phase curve 7. Determine phase margin ω 8. Design the break frequency for Gc 9. Reset system gain to compensate for Gc’s gain 10. Check bandwidth to ensure Step 1 specs are met 11. Simulate to check 12. Redesign if needed

1. Set K to satisfy steady-state specification & plot Bode diagrams for selected K 2. Find ωd where such that ΦM is 5±-12± greater than ΦM(ζd) 3. Set |Gc(jωd)| s.t Bode plot for Gc(jω)G(jω) goes through 0dB at ωd 4. Set upper break freq. @ 1 decade below ωd 5. Low freq. asymptote to be at 0 dB 6. Connect low + high freq. asymptote via -20 dB/decade line to locate low break freq. 7. Reset K to compensate for any attenuation from Gc to maintain steady-state specs 15

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PI Compensation w/ Bode Plots

PD Compensation w/ Bode Plots

1. Find closed-loop ωWB to meet TP, Tr, or Ts 2. Set K to meet steady-state 3. Pick the ωΦ = ωWB + ωcorrection, where ωcorrection is set by M,new the designer 4. Find the phase angle at the new ωΦ (given in 3) M 5. Find the contribution of the compensator = -180± + φ(ωΦM,new) + ΦM(ζd) 6. Determine K1/K2 based on the angle found in 5 7. Set K2 such that DC gain of compensator is unity

1. 2. 3. 4.

Set K to meet steady-state spec Determine the phase contribution of Gc and thus ΦM,comp Plot Bode plots for G(s) for K chosen in Step 1 Find ω and magnitude (dB) s.t. phase angle is (-180± +ΦM,comp) 5. Set break freq. to be 0.1 ω 6. Set KI s.t. magnitude of response is 0 dB at ω

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Z-Transforms

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Z-Transform Theorems

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5

Stability

Stability via the s-Plane • Routh-Hurwitz criterion for stability • More helpful to have transformations that are linear • Bilinear Transformations between s-Plane and z-Plane

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Transient Performance Specifications

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In the z-Plane

In the s-plane

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6

Cascade Compensation

Choosing T

• Design via s-plane • Transform controller into z-plane

• If T is too large (or too low sampling frequency)

• Transformation that preserves behavior of continuous compensator

• In general, upper bound on T should be

• Tustin Transformations: • Bilinear transformation that yields digital transfer function whose output matches analog version at the sampling instants

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Pole Placement • Given G(s) = 20(s+5)/[s(s+1)(s+4)], design phase-variable feedback gains to yield 9.5% overshoot w/ Ts = 0.74 sec • Locations of poles: -5.4≤j7.2, -5.1

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