Work & Virtual Work Method - University of Arkansas [PDF]

Teaching Students Work and Virtual. Work Method in Statics: A Guiding Strategy with. Illustrative Examples. Ing-Chang Jo

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Teaching Students Work and Virtual Work Method in Statics: A Guiding Strategy with Illustrative Examples Ing-Chang Jong University of Arkansas

Session 1168: Improving Mechanics of Materials 7:00 – 8:15 a.m., Monday, June 13, 2005 Oregon Convention Center F149 Portland, Oregon Proceedings of the 2005 ASEE Annual Conference & Exposition

Mechanics Division

1

Work ≠ Energy? What is work? Work is energy in transition to a system due to force or moment acting on the system through a displacement. (Note: Heat is energy in transition to a system due to temperature difference between the system and its surroundings.) Work differs from energy in that work is not a property possessed by a system, while energy (e.g., kinetic energy or potential energy) is. Work is a boundary phenomenon.

U1→ 2 = F ⋅ q = Fq&

U1→ 2 = M (∆θ ) Mechanics Division

2

Displacement center, rigid-body virtual displacement, & compatible virtual displacement B′′B′ ≈

L (δθ )2 2

A body undergoes rigid-body virtual displacement from AB to AB″. The displacement center is at A.

A body undergoes virtual displacement from position AB to position Α′B′. The displacement center is at C.

A body undergoes compatible virtual displacement from AB to AB′. The displacement center is at A. Mechanics Division

3

Virtual work Virtual work is the work done by a force or moment on a body during a virtual displacement of the body. Principle of virtual work If a body is in equilibrium, the total virtual work δ U of the external force system acting on its free body during any compatible virtual displacement of its free body is equal to zero; i.e., δU = 0 Note that the body in this principle may be a particle, a set of connected particles, a rigid body, or a system of pin-connected rigid bodies (e.g., a frame or machine). Mechanics Division

4

Method of virtual work Three major steps: Step 1: Draw the free-body (FBD) diagram. Step 2: Draw the virtual-displacement diagram (VDD) with a guiding strategy. Step 3: Set to zero the total virtual work done to solve for the unknown. One guiding strategy: In step 2, give the free body a compatible virtual displacement in such a way that the one specified unknown, but no other unknowns, will be involved in the virtual work done. Mechanics Division

5

Example 1. Determine the horizontal reaction force Dx at the fixed support D of the frame loaded as shown.

Solution. Step 1: FBD

Mechanics Division

6

Step 2: VDD to involve Dx in δ U (FBD repeated here for reference only)

Step 3: δ U = 0: 36(δθ ) + 15(6 δθ ) + 20 (8 δθ ) + 25(2 δθ ) + 10( −12 δθ ) + Dx ( −12 δθ ) = 0

Dx = 18

Dx = 18 kN ← Mechanics Division

7

If “displacement center” is not used to find δ xC , then … AB cos θ − BC cos φ = CD − AB (sin θ ) δθ + BC (sin φ ) δφ = 0

δφ = AB sin θ δθ BC sin φ δφ =

10(4/5) δθ = 2 δθ 5(4/5)

xC = AB sinθ + BC sinφ = 10sinθ + 5sinφ

δ xC = 10(cos θ ) δθ + 5(cos φ ) δφ = 10(3/5) δθ + 5(3/5) (2 δθ ) = 12 δθ ∴

δ xC = 12 δθ Mechanics Division

8

Example 2. Determine the reaction moment MD at the fixed support D of the frame loaded as shown.

Solution. Step 1: FBD

Mechanics Division

9

Step 2: VDD to involve MD in δ U (FBD repeated here for reference only)

Step 3: δ U = 0: 36(δθ ) + 15(6 δθ ) + 20(8 δθ ) + 25(2 δθ ) + 10( −12 δθ ) + MD ( − 4 δθ ) = 0 MD = 54

M D = 54 kN·m 4 Mechanics Division

10

Example 3. Determine the reaction moment MA at the fixed support A of the combined beam as shown.

Solution. Step 1: FBD

Mechanics Division

11

Step 2: VDD to involve MA in δ U

(FBD repeated here for reference only)

Step 3: δ U = 0: MA (δθ ) + 300( −3δθ ) + 200(6 δθ ) + 600( − 6 δθ ) + 300(4 δθ ) = 0 MA = 2100

MA = 2100 lb ⋅ ft 4 Mechanics Division

12

Example 4. Determine the vertical reaction force Ay at the fixed support A of the combined beam as shown.

Solution. Step 1: FBD

Mechanics Division

13

Step 2: VDD to involve Ay in δ U

(FBD repeated here for reference only)

Step 3: δ U = 0: Ay (2 δθ ) + 300( −2 δθ ) + 200(2 δθ ) + 600( − 2 δθ ) + 300 ( 43 δθ ) = 0

Ay = 500

A y = 500 lb ↑ Mechanics Division

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Concluding Remarks ƒ Work ≠ Energy. ƒ Work is energy in transition, a boundary phenomenon. ƒ Virtual work is work done on a body undergoing virtual displacement. ƒ In a nut shell, the virtual work method in Statics consists of three major steps and one guiding strategy. ƒ The three major steps are: (a) draw the FBD of the system, (b) draw the VDD of the system with a guiding strategy, and (c) set δ U = 0 to solve for the specified unknown. ƒ The guiding strategy in drawing the VDD is to give the free body a compatible virtual displacement in such a way that the one specified unknown, but no other unknowns, will be involved in the virtual work done. ƒ Virtual work method is truly a powerful method in mechanics. Mechanics Division

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Questions Mechanics Division

16

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